package leetcode._04_字符串;


/**
 * @author pppppp
 * @date 2022/1/25 16:22
 * 编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。
 *
 * 不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
 *
 * 示例 1：
 *
 * 输入：s = ["h","e","l","l","o"]
 * 输出：["o","l","l","e","h"]
 * 示例 2：
 *
 * 输入：s = ["H","a","n","n","a","h"]
 * 输出：["h","a","n","n","a","H"]
 */
public class _344_反转字符串 {
    public static void main(String[] args){
       String []s  ={"hello","memeda"};
       String []r  ={"olleh","ademem"};
        for (int i = 0; i < s.length; i++) {
            char[] charArray = s[i].toCharArray();
            reverseString(charArray);

            System.out.println(new String(charArray).equals(r[i]));
        }
    }
    public static void reverseString(char[] s) {
        for (int i = 0; i < s.length / 2; i++) {
            char t = s[s.length-1-i];
            s[s.length-1-i] = s[i];
            s[i] = t;
        }
    }
}
